Answered by : innocent-ibis
let someArray = [1, "string", false];
for (let entry of someArray) { console.log(entry); // 1, "string", false
}
var numbers = [1, 2, 3];
for (var _i = 0; _i < numbers.length; _i++) { var num = numbers[_i]; console.log(num);
}Source : https://www.typescriptlang.org/docs/handbook/iterators-and-generators.html | Last Update : Fri, 28 Feb 20
Answered by : breakable-barracuda-tiz9fcplga5k
const someArray = [9, 2, 5];
someArray.forEach((value, index) => { console.log(index); // 0, 1, 2 console.log(value); // 9, 2, 5
});Source : https://stackoverflow.com/questions/36108110/typescript-for-of-with-index-key | Last Update : Tue, 25 Aug 20
Answered by : liz-1d1t1cuhx3ot
{"tags":[{"tag":"textarea","content":"for (let i = 0; i < 10; i++) {\n console.log (\"number\" + i);\n}","code_language":"typescript"}]}Source : | Last Update : Mon, 13 Feb 23
Answered by : jealous-jay-026lgs8gfivt
for (let i = 0; i < 3; i++) { console.log ("Block statement execution no." + i);
}Source : | Last Update : Mon, 14 Dec 20
Answered by : bewildered-bison-9ihje4ktbeds
for (let entry of someArray) { console.log(entry); // 1, "string", false
}
var numbers = [1, 2, 3];
for (var _i = 0; _i < numbers.length; _i++) { var num = numbers[_i]; console.log(num);
}Source : | Last Update : Sun, 11 Oct 20
Answered by : prickly-porcupine-ftnh3gp758ln
export const markets = ['au', 'br', 'de'] as const;
export type Market = typeof markets[number];
markets.forEach((market: Market) => { console.log(market);
});Source : https://stackoverflow.com/questions/40863488/how-can-i-iterate-over-a-custom-literal-type-in-typescript | Last Update : Fri, 27 Aug 21
Answered by : nicola-migone-qjs9uo8na6ar
Not possible. If anything, you can create an array and create the type afterwards, from that arraySource : | Last Update : Sun, 27 Aug 23