How To Check If A Number Is Even Or Odd

[Solved] How To Check If A Number Is Even Or Odd | Shell - Code Explorer | yomemimo.com
Question : how to find if a value is even or odd in python

Answered by : adarsh-deen

num = int(input("Enter a Number:"))
if num % 2 == 0: print(num , "is even")
else: print(num , "is odd")

Source : | Last Update : Sun, 13 Jun 21

Question : how to check if a number is odd python

Answered by : random-programmer

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))  

Source : https://www.javatpoint.com/python-check-number-is-odd-or-even | Last Update : Thu, 28 May 20

Question : how to check if a number is even or odd in python

Answered by : impossible-impala-jed5cki5b844

num = int(input("Enter a number: "))
if (num % 2) == 0: print("{0} is Even".format(num))
else: print("{0} is Odd".format(num))

Source : | Last Update : Mon, 03 May 21

Question : how to check if a number is even or odd in python

Answered by : impossible-impala-jed5cki5b844

num = int(input("Enter a number: "))
if (num % 2) == 0: print("{0} is Even".format(num))
else: print("{0} is Odd".format(num)) 

Source : | Last Update : Mon, 03 May 21

Question : wap in python to check a number is odd or even

Answered by : adventurous-antelope-zqia4w3qywqi

num = int(input("Enter a number: "))
if (num % 2) == 0: print(num ,"is even number\n")
#CODE BY VENOM STONE
else: print(num,"is Odd number\n")
#CODE BY VENOM STONE

Source : | Last Update : Sun, 18 Apr 21

Question : Python program to check whether a number is even or odd

Answered by : helpless-hawk-m27kc3efc5x2

a = int(input("Enter the number to find odd or even "))
if (a % 2) == 0:
print("{0} is Even".format(a))
else:
print("{0} is Odd".format(a))

Source : https://inlarn.com/python-program-to-check-whether-a-number-is-even-or-odd/ | Last Update : Fri, 25 Jun 21

Question : Python Code for Checking if a number is an Odd number

Answered by : godswill-ohiole-agangan

count2 = 0
for odd_number in range(1, 20): if odd_number % 2 != 0: count2 += 1 print(odd_number)
print(f"we have {count2} odd numbers")

Source : | Last Update : Mon, 20 Jun 22

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