Question : urllib python
Answered by : awful-alpaca-lscc4ajckl7c
#Used to make requests
import urllib.request
x = urllib.request.urlopen('https://www.google.com/')
print(x.read())Source : https://pythonprogramming.net/urllib-tutorial-python-3/ | Last Update : Fri, 03 Jul 20
Question : with urllib.request.urlopen("https://
Answered by : jealous-jackal-wlo512urt0zs
import urllib.request
req = urllib.request.Request('http://www.voidspace.org.uk')
with urllib.request.urlopen(req) as response: the_page = response.read()Source : https://docs.python.org/3/howto/urllib2.html | Last Update : Thu, 23 Apr 20
Question : urllib3 python
Answered by : magnificent-marten-bzf0do5t7jae
>>> import urllib3
>>> http = urllib3.PoolManager()
>>> r = http.request('GET', 'http://httpbin.org/robots.txt')
>>> r.status
200
>>> r.data
'User-agent: *\nDisallow: /deny\n'Source : https://urllib3.readthedocs.io/en/latest/ | Last Update : Thu, 20 Aug 20
Question : urllib urlretrieve python 3
Answered by : oscar-capraro
#In Python 3.x, the urlretrieve function is located in the urllib.request module:
from urllib.request import urlretrieveSource : https://stackoverflow.com/questions/21171718/urllib-urlretrieve-file-python-3-3 | Last Update : Thu, 02 Jul 20