Question : basic code for file upload in php
Answered by : bodhaditya-mukherjee
//This is the minimal code for an image upload for first time learners
//html portion
<!DOCTYPE html>
<html>
<head> <title>ImageUpload</title>
</head>
<body> <form action="upload.php" method="post" enctype="multipart/form-data"> <label>Username</label> <input type="text" name="username"> <br> <label>UploadImage</label> <input type="file" name='myfile'> <br/> <input type="submit" value="upload"> </form>
</body>
</html> //php portion <?php $user=$_POST['username']; $image=$_FILES['myfile']; echo "Hello $user <br/>"; echo "File Name<b>::</b> ".$image['name']; move_uploaded_file($image['tmp_name'],"photos/".$image['name']); //here the "photos" folder is in same folder as the upload.php, //otherwise complete url has to be mentioned ?>
Source : | Last Update : Fri, 10 Jul 20
Question : Image upload in PHP code with databases
Answered by : sourav-attri
$file = file(1000,100000)."-".$_FILES['file']['name']; $file_loc = $_FILES['file']['tmp_name']; $file_size = $_FILES['file']['size']; $file_type = $_FILES['file']['type']; $folder="uploads/";
Source : | Last Update : Fri, 13 May 22
Question : img upload in php
Answered by : kinjal-suryavanshi
if(isset($_FILES['image'])) { $img_name = $_FILES['image']['name']; //getting user uploaded name $img_type = $_FILES['image']['type']; //getting user uploaded img type $tmp_name = $_FILES['image']['tmp_name']; //this temporary name is used to save/move file in our folder. // let's explode image and get the last name(extension) like jpg, png $img_explode = explode(".",$img_name); $img_ext = end($img_explode); //here we get the extension of an user uploaded img file $extension= ['png','jpeg','jpg','gif']; //these are some valid img extension and we are store them in array.
Source : | Last Update : Wed, 01 Sep 21
Question : php photo upload
Answered by : milan-niroula
if(isset($_FILES['image'])) { $img_name = $_FILES['image']['name']; //getting user uploaded name $img_type = $_FILES['image']['type']; //getting user uploaded img type $tmp_name = $_FILES['image']['tmp_name']; //this temporary name is used to save/move file in our folder. // let's explode image and get the last name(extension) like jpg, png $img_explode = explode(".",$img_name); $img_ext = end($img_explode); //here we get the extension of an user uploaded img file $extension= ['png','jpeg','jpg','gif']; //these are some valid img extension and we are store them in array.
Source : https://www.codegrepper.com/search.php?q=php%20photo%20upload | Last Update : Wed, 01 Jun 22
Question : how to print image just on side where upload php
Answered by : brainy-baboon-yy4hjtuf4idx
<?php $galleryPath = "Gallery/"; $descriptions = new DOMDocument("1.0"); $descriptions->appendChild($descriptions->createElement("files")); while (($uploadedFile = UploadedFiles::fetchNext()) != null){ $sourceFile = $uploadedFile->getSourceFile(); $sourceFileName = $sourceFile->getFileName(); $descriptionsFile = $descriptions->createElement("file"); $descriptionsFile->setAttribute("name", $sourceFileName); $descriptionsFile->setAttribute("width", $sourceFile->getWidth()); $descriptionsFile->setAttribute("height", $sourceFile->getHeight()); $descriptionsFile->setAttribute("description", $uploadedFile->getDescription()); $descriptions->documentElement->appendChild($descriptionsFile); $sourceFile->save($galleryPath. "/" .$sourceFileName); } $descriptions->save("Descriptions.xml");?>
Source : https://www.aurigma.com/docs/iu/WritingClient-SideScriptandHandlingUploadusingImageUploaderPHP.htm | Last Update : Sat, 25 Jul 20