Generate Strong Password

[Solved] Generate Strong Password | Php Frameworks Symfony - Code Explorer | yomemimo.com
Question : Generate Password

Answered by : prashant-priyadarshi

public string CreatePassword(int length)
{ const string valid = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890<>.,/\\@#$%^&*()_+!:"; StringBuilder res = new StringBuilder(); Random rnd = new Random(); while (0 < length--) { res.Append(valid[rnd.Next(valid.Length)]); } return res.ToString();
}

Source : https://stackoverflow.com/questions/54991/generating-random-passwords | Last Update : Fri, 25 Nov 22

Question : random password generator

Answered by : ivan-londono

function rand_string( $length ) {	$str = "";	$chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";	$size = strlen( $chars );	for( $i = 0; $i < $length; $i++ ) {	$str .= $chars[ rand( 0, $size - 1 ) ];	}	return $str;
}
//and call the function this way:
$mypass = rand_string(10);

Source : | Last Update : Mon, 16 Nov 20

Question : generate random password

Answered by : nick-triantafillidis

var btn = document.getElementById("btn");
btn.addEventListener("click", function generate() { var generatePassword = ""; var password = document.getElementById("password"); var characters = "abcdefghijklmnopqrstuvwxyz1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ!@#$%^&*?"; for (var i = 0; i < 10; i++) { generatePassword += characters.charAt( Math.floor(Math.random() * characters.length) ); } password.innerHTML = generatePassword;
});

Source : | Last Update : Thu, 03 Dec 20

Question : generate random password

Answered by : nilso-viani

const generatePassword = (length = 10, specialChars = true) => { const alphaCodesArray = Array.from(Array(26)).map((e, i) => i + 65); const uppercaseAlphabetArray = alphaCodesArray.map((letterCode) => String.fromCharCode(letterCode)); const lowercaseAlphabetArray = uppercaseAlphabetArray.map(e => e.toLowerCase()); const uppercaseAlphabet = [...uppercaseAlphabetArray].join(''); const lowercaseAlphabet = [...lowercaseAlphabetArray].join(''); const numbers = [...Array(10).keys()].join(''); const specialSymbols = typeof specialChars === 'string' ? specialChars : (specialChars ? "!@#$%^&*?" : ""); const characters = `${lowercaseAlphabet}${numbers}${uppercaseAlphabet}${specialSymbols}`; return [...Array(length).keys()].reduce(acc => acc.concat(characters.charAt(Math.floor(Math.random() * characters.length))), '');
}

Source : | Last Update : Wed, 02 Feb 22

Question : grepper subscription required

Answered by : code-grepper

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Source : | Last Update : Mon, 27 Mar 23

Question : make strong random password

Answered by : mehedi-islam-ripon

Math.random() // Generate random number, eg: 0.123456 .toString(36) // Convert to base-36 : "0.4fzyo82mvyr" .slice(-8);// Cut off last 8 characters : "yo82mvyr"

Source : https://stackoverflow.com/questions/9719570/generate-random-password-string-with-requirements-in-javascript#:~:text=Math.random()%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20//%20Generate%20random%20number%2C%20eg%3A%200.123456%0A%20%20%20%20%20%20%20%20%20%20%20%20%20.toString(36)%20%20%20%20%20%20%20%20%20%20%20//%20Convert%20%20to%20base%2D36%20%3A%20%220.4fzyo82mvyr%22%0A%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20.slice(%2D8)%3B//%20Cut%20off%20last%208%20characters%20%3A%20%22yo82mvyr%22 | Last Update : Mon, 07 Nov 22

Question : generate strong password

Answered by : jirayut-chatphet

# Generate strong password
import random
import string
def generate_password(length): """ Generate strong password with length Args: length (int): length of password Returns: password (str): strong password """ password = '' for i in range(length): password += random.choice(string.ascii_letters + string.digits) return password
def main(): length = int(6) # length of password password = generate_password(length) print(password)
if __name__ == '__main__': main()

Source : | Last Update : Sun, 17 Apr 22

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