Answered by : yellowed-yak-g2vo7w1i5e69
# Python code to demonstrate permutations
import itertools as it
print(list(it.permutations(['g', 'e', 'k'])))
Source : https://www.geeksforgeeks.org/itertools-in-python3/ | Last Update : Fri, 27 May 22
Answered by : sanskar-tanwar--066
Input: nums = [1,2,3]
Output: [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Source : https://leetcode.com/problems/permutations/ | Last Update : Sat, 30 Jul 22
Answered by : codeblack-reactor
class Solution { /** * @param Integer[] $nums * @return Integer[][] */ function permute($nums) { }
}
Source : | Last Update : Wed, 24 Aug 22
Answered by : codeblack-reactor
class Solution { public List<List<Integer>> permute(int[] nums) { }
}
Source : | Last Update : Wed, 24 Aug 22
Answered by : codeblack-reactor
function permute(nums: number[]): number[][] {
};
Source : | Last Update : Wed, 24 Aug 22
Answered by : codeblack-reactor
/** * Return an array of arrays of size *returnSize. * The sizes of the arrays are returned as *returnColumnSizes array. * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free(). */
int** permute(int* nums, int numsSize, int* returnSize, int** returnColumnSizes){
}
Source : | Last Update : Wed, 24 Aug 22
Answered by : md-murad-hossain
from itertools import permutations
from itertools import combinations
p = permutations([1,2,4]) # or permutations([1, 2, 3], 2)
for i in p: print(i)
c = combinations([1,2,3],2)
for j in c: print(j)
Source : | Last Update : Thu, 13 Oct 22
Answered by : codeblack-reactor
public class Solution { public IList<IList<int>> Permute(int[] nums) { }
}
Source : | Last Update : Wed, 24 Aug 22
Answered by : codeblack-reactor
/** * @param {number[]} nums * @return {number[][]} */
var permute = function(nums) {
};
Source : | Last Update : Wed, 24 Aug 22
Answered by : codeblack-reactor
class Solution { func permute(_ nums: [Int]) -> [[Int]] { }
}
Source : | Last Update : Wed, 24 Aug 22