Answered by : blushing-badger-gx3qb8p1v3db

import os
print(os.listdir('/path/to/folder/to/list'))

Source : | Last Update : Wed, 29 Apr 20

Answered by : moshi-wei

from os import listdir
from os.path import isfile, join
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]

Source : | Last Update : Sat, 11 Apr 20

Answered by : jjsseecc

import os
lst=os.listdir(directory)

Source : https://stackoverflow.com/questions/63684459/should-i-use-evaluate-generator-or-evaluate-to-evaluate-my-cnn-model | Last Update : Wed, 07 Jul 21

Answered by : jan-r

 import os arr = os.listdir() print(arr) >>> ['$RECYCLE.BIN', 'work.txt', '3ebooks.txt', 'documents']

Source : https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory | Last Update : Thu, 22 Apr 21

Answered by : excited-eagle-w9stcl6o7xop

import os
path = '/folder1/folder2/'
files = os.listdir(path)

Source : | Last Update : Wed, 27 Jan 21

Answered by : determined-dolphin-jsoserb5x5ka

from os import listdir
file_list = listdir(folder_path)

Source : https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory | Last Update : Wed, 27 Jan 21

Answered by : damarion-abendanon

from os import walk
from os.path import join
path = 'C:\\'
# Creates list of the items in directories (+subdirectories)
items = [join(root, file) for root, subdirs, files in walk(path) for file in files]

Source : | Last Update : Sun, 24 Apr 22

Answered by : fake-account-xl2qzg15rolu

import os arr = next(os.walk('.'))[2] print(arr) >>> ['5bs_Turismo1.pdf', '5bs_Turismo1.pptx', 'esperienza.txt']

Source : https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory | Last Update : Thu, 25 Aug 22