Answered by : jonathan-steele
from shutil import copyfile
copyfile(src, dst)
Source : https://stackoverflow.com/questions/123198/how-do-i-copy-a-file-in-python | Last Update : Mon, 09 Mar 20
Answered by : moshi-wei
from os import listdir
from os.path import isfile, join
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]
Source : | Last Update : Sat, 11 Apr 20
Answered by : bhramastra
#import OS
import os
for x in os.listdir():
if x.is_file():
# Prints only text file present in My Folder
print(x)
Source : https://www.geeksforgeeks.org/python-list-files-in-a-directory/ | Last Update : Mon, 09 May 22
Answered by : charming-caribou-khynop2559q4
import os
def get_filepaths(directory): """ This function will generate the file names in a directory tree by walking the tree either top-down or bottom-up. For each directory in the tree rooted at directory top (including top itself), it yields a 3-tuple (dirpath, dirnames, filenames). """ file_paths = [] # List which will store all of the full filepaths. # Walk the tree. for root, directories, files in os.walk(directory): for filename in files: # Join the two strings in order to form the full filepath. filepath = os.path.join(root, filename) file_paths.append(filepath) # Add it to the list. return file_paths # Self-explanatory.
# Run the above function and store its results in a variable.
full_file_paths = get_filepaths("/Users/johnny/Desktop/TEST")
Source : https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory | Last Update : Thu, 02 Apr 20
Answered by : pi-junky
from os import listdir
from os.path import isfile, join
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]
Source : https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory | Last Update : Fri, 04 Dec 20
Answered by : deepak-kumar-sachan
mylist = [f for f in glob.glob("*.txt")]
Source : https://stackoverflow.com/questions/3207219/how-do-i-list-all-files-of-a-directory | Last Update : Mon, 04 Apr 22