Penjelasan dengan langkah-langkah:

cara 1

x² - 6x - 8 = 0

salah satu akarnya = a maka memenuhi

a² - 6a - 8 = 0 ............... (1)

akar barunya (a + 1)

jika akar barunya = x maka

x = a + 1

a = (x - 1)

subtitusikan nilai (x - 1) ke (1)

(x - 1)² - 6(x - 1) - 8 = 0

x² - 2x + 1 - 6x + 6 - 8 = 0

x² - 8x - 1 = 0

cara 2

x² - 6x - 8 = 0

a = 1 ; b = -6 ; c = -8

rumus penjumlahan akar

x₁ + x₂ = -b/a = -(-6)/1

x₁ + x₂ = 6

rumus perkalian akar

x₁ . x₂ = c/a = -8/1

x₁ . x₂ = -8

misalkan akar barunya p dan q maka

p = x₁ + 1

q = x₂ + 1

p + q = (x₁ + 1) + (x₂ + 1)

p + q = (x₁ + x₂) + 2 = 6 + 2

p + q = 8

p . q = (x₁ + 1)(x₂ + 1)

p . q = x₁.x₂ + (x₁ + x₂) + 1

p . q = -8 + 6 + 1

p . q = -1

persamaan kuadrat baru

x² - (p + q) + p.q = 0

x² - 8x + (-1) = 0

x² - 8x - 1 = 0

" maaf kalau salah "