Jawab:

Penjelasan dengan langkah-langkah:

suku banyak

sisa = nilai fungsi

f(x) =  px³ + 2x²+ 5x + q

p(x) =  x² - 1

s(x)= 6x + 5

p(x)= 0

x² -1 = 0

(x - 1)(x + 1) =0

x= 1   atau x = -1

f(1) = s(1)

p(1)³ +2(1)²+ 5(1) + q =  6(1) + 5

p + 2 + 5 + q = 6 + 5

p + q + 7 = 11

p + q = 4

f(-1) = s(-1)

p(-1)³ +2(-1)²+ 5(-1) + q =  6(-1) + 5

-p + 2 - 5 + q = - 6 + 5

- p + q - 3 = - 1

- p + q = 2

eliminasi

p + q = 4

- p + q = 2 __(+)

2q= 6

q= 3

p + q= 4

p = 4 - q

p = 4-3

p = 1

nilai dari

2p + 673 q =

= 2(1) + 673(3)

= 2 + 2.019

= 2.021