To calculate the energy required to launch the rocket from Jupiter's surface into space, we need to use the formula for gravitational potential energy:

U = mgh

where U is the potential energy, m is the mass of the rocket, g is the acceleration due to gravity, and h is the height above the surface of Jupiter that the rocket needs to reach to escape its gravitational pull.

We can assume that the rocket needs to reach an infinite height to escape the gravitational pull of Jupiter, so h is equal to the radius of Jupiter, which is approximately 71,492 km.

The acceleration due to gravity on Jupiter's surface is approximately 24.79 m/s^2. However, the question states that the rocket is launched on a planet with a surface gravity of 150 ку, which is not a standard unit of measurement. Assuming that ку stands for kilograms per unit, we can convert the surface gravity of Jupiter from m/s^2 to ку using the following conversion factor:

1 ку = 9.81 m/s^2

Therefore, the surface gravity of Jupiter in ку is:

150 ку * (9.81 m/s^2 / 1 ку) = 1471.5 m/s^2

Using this value for g, we can calculate the potential energy required to launch the rocket from Jupiter's surface into space:

U = mgh = (m)(1471.5 m/s^2)(71,492,000 m) = 1.0467 x 10^15 m^2/kg/s^2

This is the amount of energy required to overcome the gravitational force of Jupiter and launch the rocket into space.

To calculate the velocity of the rocket upon launching, we can use the formula for escape velocity:

v = sqrt(2GM/r)

where v is the escape velocity, G is the gravitational constant, M is the mass of Jupiter, and r is the radius of Jupiter.

G = 6.67 x 10^-11 N(m/kg)^2

M = 1.898 x 10^27 kg

Plugging in the values and converting units to SI, we get:

v = sqrt(2(6.67 x 10^-11 N(m/kg)^2)(1.898 x 10^27 kg)/(71,492,000 m)) = 60,236 m/s

Therefore, the velocity of the rocket upon launching is approximately 60,236 m/s.