mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)

# remove duplicate from given_list using list comprehension
res = []
[res.append(x) for x in given_list if x not in res]

# HOW TO REMOVE DUPLICATES FROM A LIST:
# 1) CREATE A LIST
my_list = [1, 2, 3, 4, 5, 5, 5, 1]
# 2) CONVERT IT TO A SET AND THEN BACK INTO A LIST
my_list = list(set(my_list))
# 3) DONE!
print(my_list) #WILL PRINT: [1, 2, 3, 4, 5]

 mylist = ["a", "b", "a", "c", "c"]
mylist = list(dict.fromkeys(mylist)) print(mylist) 

olist= ["a", "a", "b", "c", "d", "e", "f"]
tlist = []
for x in range(0, len(olist)): intlist = False for y in range(0, len(tlist)): if(olist[x] == tlist[y]): intlist = True if(intlist == False): tlist.append(olist[x])
print(tlist)
#['a', 'b', 'c', 'd', 'e', 'f', 1, 2]

ar = [1,2,1,2,1,3,2]
ar = list(sorted(set(ar)))
print(ar)

bad_list = ["hi", 1, 2, 2, 3, 5, "hi", "hi"]
good_list = list(set(bad_list))

# Python 3 code to demonstrate 
# removing duplicated from list 
# using naive methods 
  
# initializing list
test_list = [1, 3, 5, 6, 3, 5, 6, 1]
print ("The original list is : " +  str(test_list))
  
# using naive method
# to remove duplicated 
# from list 
res = []
for i in test_list:
    if i not in res:
        res.append(i)
  
# printing list after removal 
print ("The list after removing duplicates : " + str(res))

''' we can convert the list to set and then back to list'''
a=[1,1,2,3,4,5,6,6,7]
'''b=(list(set(a))) # will have only unique elemenets'''

# get unique items in list aa with order maintained (python 3.7 and up)
list(dict.fromkeys(aa))